Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.2

## Class 10 Maths Chapter 5 Arithmetic Progressions Exercise 5.2

**Question 11 Which term of the A.P. 3, 15, 27, 39, … will be 132 more than its 54th term?**

**Solution: **

**Given **A.P. is 3, 15, 27, 39, …

a1 = 3

d = a2 – a1 = 15 -3 = 12

a54 = a1 + (54 – 1) d

a54 = 3 + (53) (12)

a54 = 3 + 636

a54 = 639

132 + 639 = 771 We have to find the term of this A.P. which is 771.

Let nth term be 771.

an = a1 + (n − 1) d

771 = 3 + (n – 1) 12

771 – 3 = (n – 1) 12

768 = (n-1) 12

(n-1)=64

n= 65

Therefore, 65th term was 132 more than 54th term. **Ans.**

**Question 12 Two APs have the same common difference. The difference between their 100 th term is 100, what is the difference between their 1000 th terms?**

**Solution: **

**Question 17 find the 20th term from the last term of the AP 3,8,13,….. , 253**

**Solution: **

**Given **A.P. is 3,8,13,….. , 253